怎样用matlab求解:1/(1- x)^ n?
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发布时间：2024-10-21 05:20
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热心网友
时间：2024-11-03 00:26
f'(x) = 1/(1-x)^2 =>f'(0)/1! = 1
...
f^(n)(x) = n!/(1-x)^(n+1) =>f^(n)(0)/n! = 1
f(x) = f(0) +[f'(0)/1!]x +[f''(0)/2!]x^2+...+[f^(n)(0)/n!]x^n+...
1/(1-x) =1+x+x^2+....+x^n+....
1/(1-x) = ∑(n:0->∞) x^n
两边乘以 x
x/(1-x) = ∑(n:0->∞) x^(n+1)
= ∑(n:1->∞) x^n
